" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
u = 2x - 1 ⇒ u’ = 2
v = (1 - 4x)⁵ ⇒ v’ = 5(1 - 4x)⁴ . (-4) ⇒ v’ = -20(1 - 4x)⁴
h’(x) = u’v + v’u
= 2(1 - 4x)⁵ + (-20(1 - 4x)⁴)(2x - 1), atau
= 2(1 - 4x)⁵ - 20(1 - 4x)⁴ (2x - 1)
= 2[(1 - 4x)⁵ - 10(1 - 4x)⁴ (2x - 1)]
= 2(1 - 4x)⁴ [(1 - 4x) - 10(2x - 1)]
= 2(1 - 4x)⁴ [1 - 4x - 20x + 10]
h’(x) = 2(11 - 24x)(1 - 4x)⁴
h’(x) = (22 - 48x)(1 - 4x)⁴ (Jawaban D)