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f(-1) = (-1)² - 4(-1) + 3 = 1 + 4 + 3 = 8
f(0) = (0)² - 4(0) + 3 = 0 - 0 + 3 = 3
f(1) = 1² - 4(1) + 3 = 1 - 4 + 3 = 0
f(2) = 2² - 4(2) + 3 = 4 - 8 + 3 = (-1)
f(3) = 3² - 4(3) + 3 = 9 - 12 + 3 = 0
f(4) = 4² - 4(4) + 3 = 16 - 16 + 3 = 3
daerah hasil {-1 <_ x <_ 8}
b) (-1,8) (0,3) (1,0) (2,-1) (3,0) (4,0)