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f(2) = (2 + a) + 3 = 7
= 2 + a + 3 = 7
= 5 + a = 7
= a = 2
(a) f(x) = (x + 2) + 3
(b) f(-1) = (-1 + 2) + 3
= 1 + 3
= 4
(c) f(-2) = (-2 + 2) + 3
= 3
f(-1) = (-1 + 2) + 3
= 1 + 3
= 4
Jadi 3 + 4 = 7
(d) f(2x - 5) = ((2x - 5) + 2) + 3
= 2x = -5 + 2 + 3
= 2x = 6
= x = 3