Diketahui f(x) = ax+b, jika f(2)= 19 dan f(4)=11,tentukan : a) Nilai a dan b b) f(x)
ayiliya
A) f(2) = a(2) + b f(4) = a(4) + b 19 = 2a + b 11 = 4a + b eliminasi persamaan di atas 2a + b = 19 4a + b = 11 ----------------- - -2a = 8 a = -4 2a + b = 19 2(-4) + b = 19 -8 + b = 19 b = 19 + 8 = 27 jadi a = -4 dan b = 27
19 = 2a + b 11 = 4a + b
eliminasi persamaan di atas
2a + b = 19
4a + b = 11
----------------- -
-2a = 8
a = -4
2a + b = 19
2(-4) + b = 19
-8 + b = 19
b = 19 + 8 = 27
jadi a = -4 dan b = 27
b. f(x) = ax + b
= -4x + 27