Diketahui f(x) = ax+1 dan f(6) = 4 Tentukan a.) rumus fungsinya b) Nilai f(-2) c) nilai f(-2) + f(2)
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F(6) = a(6)+1 4. = 6a +1 3. = 6a 3/6 = a 1/2 = a a) f(x) = 1/2x +1 b) f(-2) =1/2(-2) +1 = -1+1 = 0 c) cara nya sama seperti b. dicoba sendiri yah. pakai rumus f(x)=1/2x+1
4. = 6a +1
3. = 6a
3/6 = a
1/2 = a
a) f(x) = 1/2x +1
b) f(-2) =1/2(-2) +1
= -1+1
= 0
c) cara nya sama seperti b. dicoba sendiri yah. pakai rumus f(x)=1/2x+1