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g(f(a)) = 3
g(1-3a) = 3
(1-3a)² - 1 = 3
1 - 6a + 9a² - 1 - 3 = 0
9a² - 6a - 3 = 0 --> kedua ruas dibagi 3
3a² - 2a - 1 = 0
(3a + 1) (a - 1) = 0
a = -1/3 atau a = 1
semoga membantu ya :)