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maka
f(3y + 1) = 6y + 3
f(3 · (x - 1)/3) + 1) = 6 · (x - 1)/3 + 3
f(x - 1 + 1) = 2(x - 1) + 3
f(x) = 2x - 2 + 3
f(x) = 2x + 1
jadi, f(x) = 2x + 1