Diketahui f (×)= a× + b dengan f (3) =1 dan f (1)=-1. Tentukan: A. nilai a dan b B. bentuk fungsi C. nilai f(-2)
Audiapus
F (x) = ax +b f (3) = a (3) + b = 1 f (3)= 3a + b =1 ... (1)
f(1) = a(1) + b = -1 f (1) = a + b =-1 ... (2)
3a + b = 1 a + b = -1 ___________ - 2a = 2 a = 2/2 a = 1
a + b = -1 1 + b = -1 b = -1 -1 b = -2
jadi a = 1 dan b = -2
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udink
A. buat persamaan f(x)= ax+b f(3)=1 maka 3a+b=1 .........................(1) f(1)=-1 maka a+b=-1 ..........................(2) ----------- -- 2a =2 a=1 maka b=-1-1=-2 b. bentuk fungsinya f(x)=x-2 c. nilai f(-2)=-2-2=-4
f (3) = a (3) + b = 1
f (3)= 3a + b =1 ... (1)
f(1) = a(1) + b = -1
f (1) = a + b =-1 ... (2)
3a + b = 1
a + b = -1
___________ -
2a = 2
a = 2/2
a = 1
a + b = -1
1 + b = -1
b = -1 -1
b = -2
jadi a = 1 dan b = -2
f(x)= ax+b
f(3)=1 maka 3a+b=1 .........................(1)
f(1)=-1 maka a+b=-1 ..........................(2)
----------- --
2a =2
a=1 maka b=-1-1=-2
b. bentuk fungsinya f(x)=x-2
c. nilai f(-2)=-2-2=-4