Diketahui barisan geometri dengan U3=96 dan U7=6..nilai U10 adalah....
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![r = \sqrt[(7-3)]{ \frac{6}{96} } \\ r=\sqrt[4]{ \frac{1}{16} } \\ r= \frac{1}{2} \\ \\ U10=U7.r^3 \\ U10=6. \frac{1}{2}}^3 \\ U10=6. \frac{1}{8} \\ U10= \frac{6}{8}= \frac{3}{4}](https://tex.z-dn.net/?f=r+%3D+%5Csqrt%5B%287-3%29%5D%7B+%5Cfrac%7B6%7D%7B96%7D+%7D++%5C%5C+r%3D%5Csqrt%5B4%5D%7B+%5Cfrac%7B1%7D%7B16%7D+%7D+%5C%5C+r%3D+%5Cfrac%7B1%7D%7B2%7D++%5C%5C++%5C%5C+U10%3DU7.r%5E3+%5C%5C+U10%3D6.+%5Cfrac%7B1%7D%7B2%7D%7D%5E3+%5C%5C+U10%3D6.+%5Cfrac%7B1%7D%7B8%7D+++%5C%5C+U10%3D+%5Cfrac%7B6%7D%7B8%7D%3D+%5Cfrac%7B3%7D%7B4%7D+ "r = \sqrt[(7-3)]{ \frac{6}{96} } \\ r=\sqrt[4]{ \frac{1}{16} } \\ r= \frac{1}{2} \\ \\ U10=U7.r^3 \\ U10=6. \frac{1}{2}}^3 \\ U10=6. \frac{1}{8} \\ U10= \frac{6}{8}= \frac{3}{4}")
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