Diketahui barisan aritmetika suku ke 2 dan suku ke 5 berturut turut -3 dan 6. suku ke 20 barisan tersebut adalah...
IndahFaridah28
Dik : U2 = -3 U5 = 6 b = 6-(-3)/5-2 = 9/3 = 3 Dit : U20 = ? Jawab : Un = a + (n-1)b U5 = a + (5-1)3 6 = a + (4)3 6 = a + 12 6-12 = a -6 = a a = -6
U5 = 6
b = 6-(-3)/5-2 = 9/3 = 3
Dit : U20 = ?
Jawab :
Un = a + (n-1)b
U5 = a + (5-1)3
6 = a + (4)3
6 = a + 12
6-12 = a
-6 = a
a = -6
maka, U20 = a + (n-1)b
= -6 + (20-1)3
= -6 + (19)3
= -6 + 57
U20 = 51
Semoga membantu. :)
( 6 + 3 ) : ( 5 - 2 ) = 3
Awal :
-3 = a + b
-3 = a + 3
a = -6
Suku ke 20 :
U₂₀ = a + 19b
= -6 + 19 × 3
= 51