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27 9 3 1
SETIAP ke suku(U) selanjutnya, dibagi 3,
barisan geometri 27,9,3...
Ditanyakan :
S₉ = ?
Penyelesaian :
U₂ = a·r¹ = 9
U₃ = a·r² = 3
Maka :
a·r² = 3
a·r·r = 3
9·r = 3
r = 3/9
r = 1/3
Sehingga ;
a·r = 9
a(1/3) = 9
a = 9 x 3
a = 27
Jadi suku ke-7 :
Sederhanakan menjadi :