Diketahui balok berukuran P=5 L=4 T=12. hitunglah luas permukaan balok tanpa tutup.
Alcander
Lp = (2 (pt + lt )) + pl = (2 (5 x 12 + 4 x 12)) + 5 x 4 = (2 x (60 + 48)) + 20 = 216 + 20 = 236 cm²
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inesnaila
Sisi Depan dan Belakang = 2 × ( 5 × 12 ) = 2 × 60 = 120 cm² Sisi Kanan dan Kiri = 2 × ( 4 × 12 ) = 2 × 48 = 96 cm² Sisi Alas = 5 × 4 = 20 cm² Luas permukaan tanpa alas = 120 + 96 + 20 = 236 cm²
= (2 (5 x 12 + 4 x 12)) + 5 x 4
= (2 x (60 + 48)) + 20
= 216 + 20
= 236 cm²
Sisi Kanan dan Kiri = 2 × ( 4 × 12 ) = 2 × 48 = 96 cm²
Sisi Alas = 5 × 4 = 20 cm²
Luas permukaan tanpa alas = 120 + 96 + 20 = 236 cm²