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BC² = AB² + AC²
BC² = 10² + 24²
BC² = 100 + 576
BC² = 676
BC = √676
BC = 26 cm
s = 1/2 (AB + BC +AC)
= 1/2 (10 + 26 + 24)
= 1/2 (60)
= 30 cm
r dalam = √s (s-a)(s-b)(s-c)
= √30 (30-26)(30-24)(30-10)
= √30 (4)(6)(20)
= √30 (480)
= √14400
= 120 / s
= 120 / 30
= 4 cm
Jadi, jari-jari lingkaran dalam pada ΔABC adlah 4 cm
Sekian dan Terima kasih......=)
smoga membantu....
ΔABC adalah siku-siku di A
AB = 10 cm
AC = 24 cm
BC =
BC =
BC =
BC = 26 cm
s=
s=
s=
s = 30 cm
L =
L =
L = 120
=
=
= 4 cm
Jadi, panjang jari-jari lingkaran dalam segitiga ABC adalah 4 cm.
semoga membantu :)