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2Fe + 2HCL --> Fe2Cl + H2
cari mol Fe
n=N/Na
= 3.01x10^23/6.02x10^23
=0.5mol
dari sana perbanding koefisien Fe:H2= 2:1
jadi kalo mol nya Fe=0.5 maka mol H2 jadi 0.25
mol H2=0.25
sekarang hitung volumenya
pada keadaan standar
22.4L/mol=VH2/0.25
Vh2=22.4x0.25
vh2=5.6 l;iter