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2P(s) + O₂(g) + 3Cl₂ → 2POCl₃(g) ΔH = -1.150 kj [kalikan 1/2]
H₂(g) + Cl₂(g) → 2HCl (g) ΔH = -184 kj [tetap]
2P(s) + 5Cl₂(g) → 2PCl₅ (g) ΔH = - 640 kj [reaksi dibalik, kalikan 1/2]
2H₂(g) + O₂(g) → 2H₂O(g) ΔH = - 482 kj [reaksi dibalik, kalikan 1/2]
Berdasarkan perlakuan di atas, maka telah menjadi sebagai berikut:
PCl₅ (g) → P(s) + 5/2 Cl₂(g) ΔH = + 320 kj
H₂O(g) → 1/2 O₂(g) + H₂(g) ΔH = + 241 kj
P(s) + 1/2 O₂(g) + 3/2 Cl₂ → POCl₃(g) ΔH = - 575 kj
H₂(g) + Cl₂(g) → 2HCl (g) ΔH = -184 kj
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PCl₅ (g) + H₂O(g) → POCl₃(g) + 2HCl (g) ΔH = -198 kj