Question

Diket;8 bola berwarna putih
4 bola warna kuning
6 bola warna merah
Ditanya; peluang terambilnya a)bola warna merah
b)bola warna kuning

MOHON BANTUANNYA YAH.... PAKE CARA....
TRIMS^_^

Answer 1

N(S) = 8+4+6 = 18 bola
a. Peluang terambil bola berwarna merah = 6/18 = 1/3
b. Peluang terambil bola berwarna kuning = 4/18 = 2/9

Good Luck! :D

Answer 2

N(s) = 8 + 4 + 6 = 18.
a. bola merah = 6 n(a)
P(a) = n(a)/n(s) = 6/18 = 1/3
b. bola kuning = 4 n(b)
P(b) = n(b)/n(s) = 4/18 = 2/9