Diket jari-jari alas sebuah kerucut 28cm & Luas selutuh permukaan. 5.544 cm Hitunglah: A. Panjang garis pelukisnya B. Tinggi kerucutnya C. Volume kerucut
Galladeaviero
R= 28 L = π r( r+s) = 5.544 L = 88(28+s) = 5.544 28+ s = 63 a) s = 35 b) t=√(s²-r²) =21 c) V = 1/3 π r² t = 616
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young29
A.) lp = πr (s+r) 5.544 = 22/7 * 28 (s+28) 5.544 = 88 (s+28) 5.544 = 88s + 2.264 88s = 5.544 - 2.264 s = 3080 = 35 cm 88 b.) t² = s² - r² = 35² - 28² = 1.225 - 784 = 441 t = √441 = 21 cm c) v = 1πr²t 3 = 1 * 22 * 28² * 21 3 7 = 1.7248 cm²
L = π r( r+s) = 5.544
L = 88(28+s) = 5.544
28+ s = 63
a) s = 35
b) t=√(s²-r²) =21
c) V = 1/3 π r² t = 616
5.544 = 22/7 * 28 (s+28)
5.544 = 88 (s+28)
5.544 = 88s + 2.264
88s = 5.544 - 2.264
s = 3080 = 35 cm
88
b.) t² = s² - r²
= 35² - 28²
= 1.225 - 784
= 441
t = √441 = 21 cm
c) v = 1πr²t
3
= 1 * 22 * 28² * 21
3 7
= 1.7248 cm²