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3=a+b.....(1)
f(-2)=a.(-2)+b
6=-2a+b3....(2)
3=a+b _
3=-3a
a=-1
b=4
f(x)=-x+4
f(-2)= 6 ⇒ -2a + b = 6
-
3a = -3
a = -1
⇒a + b = 3
-1 +b = 3
b = 3 + 1
b = 4
f (x) = -x + 4