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X = 2y + 5
ii) 2x + 3z = 12
iii) y + 2z = 3
y = 3 - 2z
Jadi, x + y
= 2y + 5 + 3 - 2z
= 8 + 2y - 2z
dik : X - 2y = 5; 2x + 3z = 12, y + 2z = 3. nilai x + y = .....
Jawaban :
Persamaan :
x - 2y = 5.................[1]
2x + 3z = 12............[2]
y + 2z = 3...............[3]
Eliminasi persamaan 1 dan 2 :
x - 2y = 5 |×2 | ⇒ 2x - 4y = 10
2x + 3z = 12 |×1 | ⇒ 2x + 3z = 12 -
- 4y - 3z = -2....................[4]
Eliminasi persamaan 3 dan 4 :
y + 2z = 3 |×4 | ⇒ 4y + 8z = 12
-4y - 3z = -2 |×1 | ⇒ -4y - 3z = - 2 +
5z = 10
z = 10/5
z = 2
Untuk nilai y, subtitusi z = 2 ke persamaan 3 :
y + 2z = 3
y + 2(2) = 3
y + 4 = 3
y = 3 - 4
y = - 1
Untuk nilai x, subtitusi y = - 1 , ke persamaan 1 :
x - 2y = 5
x - 2(-1) = 5
x + 2 = 5
x = 5 - 2
x = 3
Jadi untuk nilai :
x + y
= 3 + (-1)
= 3 - 1
= 2