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Luas alas kerucut = π r²
154 = ( 22/7)r²
r² = 7/22 × 154
r² = 7 × 7
r² = 7²
r = 7 cm
Luas selimut = π r s
500 = 22/7 × 7 s
500 = 22 s
s = 500/22
s = 250/11
Menurut teorema pythagoras,
pada kerucut berlaku t² + r² = s²
sehingga
t² + 7² = (250/11)²
t² = (250/11)² - 7²
t² = 62500/121 - 49
t² = 62500/121 - 49×121/121
t² = 62500/121 - 5929/121
t² = 56571/121
t² = 467,5289256198
t = √467,5289256198
t = 21,6224172011 cm
Jawab
Tinggi kerucut adalah 21,6224172011 cm
Selamat belajar !
Wello1☺☺☺