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kaki kambing = 4 dan kaki ayam = 2
k + a = 13
4k + 2a = 32
k + a = 13
2k + 2a = 26
2a = 26 - 2k
4k + 2a = 32
4k + 26 - 2k = 32
2k = 32 - 26
2k = 6
k = 6/2
k = 3 ekor
k + a = 13
3 + a = 13
a = 13 - 3
a = 10 ekor
jadi jumlah kambing = 3 ekor dan jumlah ayam = 10 ekor
y = ayam (jml kaki 2)
- Dicari dengan persamaan dulu [mencari kambing] :
x + y =13 | *2 | 2x + 2y = 26
4x + 2y =32 | *2 | 4x + 2y = 32
___________ -
-2x = -6
x = 3 [Kambing = 3 ekor]
- Dicari persamaan [mencari ayam]
x + y = 13 | *4 | 4x + 4y = 52
4x + 2y = 32 | *1 | 4x + 2y = 32
___________ -
2y = 20
y = 10 [Ayam = 10 ekor]
- Dicek =
x = 3 | y = 10
x + y = 10 + 3 = 13
4x + 2y = 4*3 + 2*10 = 12 + 20 = 32
JAWABAN =
Kambing = 3 ekor
Ayam = 10 ekor
^Maaf kalau salah.