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kambing = k
eliminasi
a +k =15 I2I 2a + 2k = 30
2a+4k=40 I1I 2a + 4k = 40
__________-
-2k =-10
k=5
substitusi
a + k = 15
a + 5 = 15
a =15- 5
a= 10
jadi kambing ada 5 sedangkan ayam ada 10
ayam =x
kambing = y
diket : x+y=15
kan kaki ayam =2, kaki kambing =4 ,maka
2x+4y =40
dita : x = ? y=?
jawab nya : pakai metode eliminasi
x + y = 15 disamain koefisien nya dulu (X 4) ⇒ 4x +4y =60
2x+4y =40 ⇒⇒⇒⇒ 2x +4y = 40
dikurangi
2x = 20
x = 20 : 2
x = 10
jadi banyak ayam = 10 ekor
kambing = 10 + y =15
y = 15 - 10
y = 5
jadi banyak kambing = 5 ekor
maaf kalau salah