Didalam 100 ml larutan CH3COOH 0,1 M konsentrasi ion H+nya adalah .? ka CH3COOH=1,75x10-5
sama caranya ya gan..!!tnks
intankrisdian8
Karena CH3COOH merupakan asam lemah maka rumusnya : [H+] = akar Ka x Ma [H+] = akar 1,75x10^-5 x 0,1 [H+] = akar1,75x10^-6 [H+] = 1,32x10^-3
[H+] = akar Ka x Ma [H+] = akar 1,75x10^-5 x 0,1
[H+] = akar1,75x10^-6
[H+] = 1,32x10^-3