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mol NH4Cl = 1,3375 ÷ 53,5 = 0,025
OH^- = Kb × (mol basa ÷ mol garam)
= 10^-5 × (0,05 ÷ 0,025)
= 2 × 10^-5
pOH = 5 - log 2 maka
pH = 14 - (5 - log 2)
= 9 + log 2