Diberikan sebuah kerucut yang memiliki jari-jari sebesar r = 30 cm dan garis pelukis s = 50 cm. Tentukan: a) tinggi kerucut b) volume kerucut c) luas selimut kerucut d) luas permukaan kerucut
Asruula) tinggi kerucut t₂ = √50² - 30² t₂ = √2500 - 900 t₂ = √1600 t₂ = 40 cm
b) volume kerucut V = 1/3 π r₂ t V = 1/3 x 3,14 x × 30 x 30 x 40 V = 37.680 cm3
c) luas selimut kerucut L = πrs L = 3,14 x 30 x 50 L = 4 710 cm2
d) luas permukaan kerucut Lp = π r (s + r) Lp = 3,14 x 30 (50 + 30) Lp = 3,14 x 30 x 80 Lp = 7.536 cm²
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marlenia16
A. tinggi kerucut = 50² - 30² = = = 40 cm b. volume kerucut = × π × r² × t = × 3,14 × 30 × 30 × 40 = 37.680 cm³ c. luas selimut kerucut = π × r × s = 3,14 × 30 × 50 = 4.710 cm² d. luas permukaan kerucut = π × r (s + r) = 3,14 × 30 (50 + 30) = 94,2 × 80 = 7.536 cm²
t₂ = √50² - 30²
t₂ = √2500 - 900
t₂ = √1600
t₂ = 40 cm
b) volume kerucut
V = 1/3 π r₂ t
V = 1/3 x 3,14 x × 30 x 30 x 40
V = 37.680 cm3
c) luas selimut kerucut
L = πrs
L = 3,14 x 30 x 50
L = 4 710 cm2
d) luas permukaan kerucut
Lp = π r (s + r)
Lp = 3,14 x 30 (50 + 30)
Lp = 3,14 x 30 x 80
Lp = 7.536 cm²
=
=
= 40 cm
b. volume kerucut = × π × r² × t
= × 3,14 × 30 × 30 × 40
= 37.680 cm³
c. luas selimut kerucut = π × r × s
= 3,14 × 30 × 50
= 4.710 cm²
d. luas permukaan kerucut = π × r (s + r)
= 3,14 × 30 (50 + 30)
= 94,2 × 80
= 7.536 cm²