cos A = (AB² + AC² - BC²) / ( 2 AB AC) cos A = (36 + 9 - 63)/ (2)(6)(3) cos A = (-18)/(36) = - 1/2 = cos 120 < A = 120 Luas Δ ABC = 1/2 (AB)(AC) sin < A Luas alas = 1/2 (6)(3)(sin 120) Luas alas = 9 (1/2 √3)
Volume prisma = Luas alas x t V = 9/2 √3 (20) V = 90√3 cm³
Verified answer
JawabAlas Δ ABC
cos A = (AB² + AC² - BC²) / ( 2 AB AC)
cos A = (36 + 9 - 63)/ (2)(6)(3)
cos A = (-18)/(36) = - 1/2 = cos 120
< A = 120
Luas Δ ABC = 1/2 (AB)(AC) sin < A
Luas alas = 1/2 (6)(3)(sin 120)
Luas alas = 9 (1/2 √3)
Volume prisma = Luas alas x t
V = 9/2 √3 (20)
V = 90√3 cm³