Diberikan :
f(x) = x^2 + 3
g(x) = 2x - 3
h(x) = 5
Tentukan :
1. (f o g o h)(2)
2. (g o h o g)(2)
3. (f o h o f)(2)
4. (f o f o h)(x+3)
5. (h o g o f)(x+1)
f(x) = x^2 + 3
g(x) = 2x - 3
h(x) = 5
Tentukan :
1. (f o g o h)(2)
2. (g o h o g)(2)
3. (f o h o f)(2)
4. (f o f o h)(x+3)
5. (h o g o f)(x+1)
no.2 cranya
= go(hog)(2)
=go(5)---> (jika hog tetap 5 karena tidak ada variabel x, h(x) =5 itu konstanta
=2(5)-3
=7(2) --> dpt 2 krna dr soalnya
= 14
no.3
=fo(hof) ---> sma sprti no 2 alasannya
= 5 pangkat 2 + 3
= 25 + 3
= 28(2)
= 56
no.4
=fo(foh)
=fo(5pangkat 2 + 3)
=fo(28)
=28 pangkat 2 + 3
= 787(x+3)
=787x + 2361
no.5
=ho(gof)
= ho(2(x kuadrat +3)-3)
= ho(2x kuadrat +6-3)
=ho(2x kuadrat + 3)
=5(x+1)
=5x + 5