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mobil = y
x + y = 150 | x2 | 2x+2y=300
2x + 4y = 420 | x1 | 2x+4y=420
-2y=-120
y=60
x+y=150
x=150-y
x=90
Pendapatan = (4000.y) + (2500.x)
= (4000.60)+(2500.90)
= 240.000+ 225.000 = 465.000 [CMIIW]
maka
x + y = 150
2x + 4y = 420
Ditanya 4000y + 2500x = ...?
gunakan metode eliminasi,
2x + 2y = 300
2x + 4y = 420
_____________ -
-2y = -120
y = 60
substitusikan,
x + y = 150
x + 60 = 150
x = 90
Jadi penghasilan tukang parkir =
4000(60) + 2500(90) =
465.000