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a, a+b, a+5b
a + b a + 5b
____ = _______
a a + b
(a + b) (a + b) = a (a + 5b)
a² + b² + 2ab = a² + 5ab
b² + 2ab = 5ab
b² + 2ab - 5ab = 0
b² - 3ab = 0
b (b - 3a) = 0
b = 0
b = 3a. . . . . . . (1)
Deret aritmatikanya :
a, a+b, x, y, z
x + y + z = 15
U₃ + U₄ + U₅ = 15
(a + 2b) + (a + 3b) + (a + 4b) = 15
3a + 9b = 15. . . . (2)
Substitusi persamaan 1 ke persamaan 2
3a + 9b = 15
3a + 9(3a) = 15
3a + 27a = 15
30a = 15
a = ½
b = 3a
b = 3(½)
b = 3/2
didapat nilai
a = ½
b = 3/2
Un = a + (n-1)b
U₁₀ = ½ + (10-1)3/2
U₁₀ = ½ + 27/2
U₁₀ = 28/2
U₁₀ = 14
Jadi, suku ke-10 barisan aritmatika tersebut adalah 14