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(1/4 x + 1/6 y = 1) × 12 → 3x + 2y = 12
(1/2 x + 1/2 y = 1) × 4 → 2x + 2y = 4
Eliminasikan kedua persamaan tersebut
3x + 2y = 12
2x + 2y = 4
_________ -
x = 8
Masukkan nilai x ke persamaan 2x + 2y = 4
2x + 2y = 4
2(8) + 2y = 4
16 + 2y = 4
2y = 4 - 16
2y = -12
y = -12/2 = -6
x = p → 8 = p
y = q → -6 = q
2p + q = 2(8) + (-6) = 16 - 6 = 10 (D)
22.
BF = 1/2 × AB = 1/2 × 24 = 12 cm
Untuk mencari CF, gunakanlah cara pythagoras
CF = √(BC^2 - BF^2)
= √(20^2 - 12^2)
= √(400 - 144)
= √256 = 16 cm
t jajargenjang = CF = 16 cm
L jajargenjang = CF × BD
240 = 16 × BD
BD = 240/16 = 15 cm
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