3. Diketahui:
a = 8 m
t = 6m
tinggi = 15 m
Ditanyakan:
panjang rusuk
Jawab:
sisi miring = s = √(8²+6²) = 10 m
panjang rusuk = 2(a+t+s)+3tinggi
= 2(8+6+10)+3(15) m
= 2(24)+45 m
= 48+45
= 93 m (D)
4. Diketahui:
d1 = 12 cm
d2 = 18 cm
t= 15 cm
panjang kawat yg tak terpakai
sisi alas = √((1/2 d1)²+(1/2 d2)²)
= √((1/2. 12)²+(1/2. 18))²
= √(6²+9²)
= √(36+81)
= √117
= 3√13 cm
panjang kawat = 4(2 sisi alas+t)
= 4(2(3√13)+15) cm
= 4(6√13+15) cm
= 24√13 + 60 cm
kawat yg tak terpakai = 1,5 m - (24√3+60)cm
= 150 cm - (24√3+60)cm
= 150 cm -24√3 cm - 60 cm
= 90 - 24√3 cm
Mapel: Matematika
Kelas: 8
Materi: Bangun Ruang Sisi Datar
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3. Diketahui:
a = 8 m
t = 6m
tinggi = 15 m
Ditanyakan:
panjang rusuk
Jawab:
sisi miring = s = √(8²+6²) = 10 m
panjang rusuk = 2(a+t+s)+3tinggi
= 2(8+6+10)+3(15) m
= 2(24)+45 m
= 48+45
= 93 m (D)
4. Diketahui:
d1 = 12 cm
d2 = 18 cm
t= 15 cm
Ditanyakan:
panjang kawat yg tak terpakai
Jawab:
sisi alas = √((1/2 d1)²+(1/2 d2)²)
= √((1/2. 12)²+(1/2. 18))²
= √(6²+9²)
= √(36+81)
= √117
= 3√13 cm
panjang kawat = 4(2 sisi alas+t)
= 4(2(3√13)+15) cm
= 4(6√13+15) cm
= 24√13 + 60 cm
kawat yg tak terpakai = 1,5 m - (24√3+60)cm
= 150 cm - (24√3+60)cm
= 150 cm -24√3 cm - 60 cm
= 90 - 24√3 cm
Mapel: Matematika
Kelas: 8
Materi: Bangun Ruang Sisi Datar