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(Y - K)² = 4P(X - H) (H,K) = (5,2)
(Y - 2)² = 4P(X - 5)
Donde parámetro p representa la distancia del vértice al foco En este caso
P = 3 - 5 = -2
(Y - 2)² = 4(-2)(X - 5)
(Y - 2)² = -8X + 40
Y² - 4Y + 4 = -8X + 40
Y² - 4Y + 8X + 4 - 40 = 0
Y² + 8X - 4Y - 36 = 0
Te anexo La grafica
Donde Punto A Vertice (5 , 2)
Punto B Foco (3,2)