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entonces Ek= 1/2 m v²
reemplazamos
250 = 1/2 * 3 * v²
500 = 3 * v²
√ 500/3 = v
12.91≈V
la segunda debe ser energia potencial, entonces
Ep = m g h
reemplazamos, se usara gravedad = 9.8 m/ s²
90 = 5* 9.8 * h
90= 49 * h
1.84 m = h
EK=1/2mv²
Despejamos v:
v=√(2*Ek)/m
v=√(2*250J)/3kg
v=12,9m/s
En el otro caso, sabemo que:
Epg=mgh
Despejamos h:
h=(Epg)/mg
h=(90J)/5kg*9,8m/s²
h=1,8m