Determinar el peso molecular de las siguientes sustancias:
a.)C6H12O6 b).Fe2(SO4)3 c.)NH4NO3
a.)C6H12O6 b).Fe2(SO4)3 c.)NH4NO3
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C = 12g
H = 1g
O = 16g
6(12)+12(1)+6(16) = 180
C6H12O6 = 180g/mol
b) Fe2(SO4)3
Fe = 55g
S = 32g
O = 16g
2(55)+3(32)+12(16) = 398
Fe2(SO4)3 = 398g/mol
c) NH4NO3
N = 14g
H = 1g
O = 16g
2(14)+4(1)+3(16) = 80
NH4NO3 = 80g/mol