Respuesta:
Explicación paso a paso:
Radio: r = 3cm
Generatriz: g = 6cm
[tex]\pi = 3.14[/tex]
Area Lateral: [tex]A_{L} = ?[/tex]
Fórmula:
[tex]A_{L} = \pi rg[/tex]
[tex]A_{L} = \pi (3cm)(6cm) = 18\pi (cm^{2} )[/tex]
[tex]A _{L} = 18\pi (cm^{2} )[/tex]
[tex]A_{L} = 18(3.14)cm^{2}[/tex]
[tex]A_{L} = 56.62cm^{2}[/tex]
RESPUESTA:
[tex]18\pi (cm^{2} )[/tex] ó [tex]56.62 cm^{2}[/tex]
_________________________________________________________
Radio: r = 5 m
Generatriz: g = 12 m
[tex]A_{T} = \pi r (r+g)[/tex]
[tex]A_{T} = \pi (5m) [ 5m + 12 m ] = (5\pi m)[ 17m] = 85\pi (m^{2} )[/tex]
[tex]A_{T} = 85\pi (m^{2} )[/tex]
[tex]A_{T} = 85( 3.14) m^{2}[/tex]
[tex]A_{T} = 266.9(m^{2})[/tex]
[tex]85\pi (m^{2} )[/tex] ó [tex]266.9 (m^{2} )[/tex]
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Respuesta:
Explicación paso a paso:
Radio: r = 3cm
Generatriz: g = 6cm
[tex]\pi = 3.14[/tex]
Area Lateral: [tex]A_{L} = ?[/tex]
Fórmula:
[tex]A_{L} = \pi rg[/tex]
[tex]A_{L} = \pi (3cm)(6cm) = 18\pi (cm^{2} )[/tex]
[tex]A _{L} = 18\pi (cm^{2} )[/tex]
[tex]A_{L} = 18(3.14)cm^{2}[/tex]
[tex]A_{L} = 56.62cm^{2}[/tex]
RESPUESTA:
[tex]18\pi (cm^{2} )[/tex] ó [tex]56.62 cm^{2}[/tex]
_________________________________________________________
Radio: r = 5 m
Generatriz: g = 12 m
[tex]\pi = 3.14[/tex]
Area Lateral: [tex]A_{L} = ?[/tex]
Fórmula:
[tex]A_{T} = \pi r (r+g)[/tex]
[tex]A_{T} = \pi (5m) [ 5m + 12 m ] = (5\pi m)[ 17m] = 85\pi (m^{2} )[/tex]
[tex]A_{T} = 85\pi (m^{2} )[/tex]
[tex]A_{T} = 85( 3.14) m^{2}[/tex]
[tex]A_{T} = 266.9(m^{2})[/tex]
RESPUESTA:
[tex]85\pi (m^{2} )[/tex] ó [tex]266.9 (m^{2} )[/tex]