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x² -2x +1
(x² - 1)² = (x²)² 2x² +1 = x⁴ -2x² +1
(4 +3y³)² aplicamos (a +b )² = a² +2ab +b²
4² +2(4)(3y³) +(3y³)² = 16 +24y³ +9 y⁶
(x -2)² = x² - 2(x)(2) +2² = x² -4x +4
(x-1)²
(x)²-2(x)(1)+(1)²
x²-2x+1
(x²-1)²
(x²)²-2(x²)(1)+(1)²
x⁴ -2x²+1
(4+3y³)²
(4)²+2(4)(3y³)+(3y³)²
16+24y³+9y⁶
(x-2)²
(x)²-2(x)(2)+(2)²
x²-4x+4
Espero ayude