Sebatang besi panjang 100 cm di panaskan hingga suhunya naik 100 derajat celcius.jika koefisien muai besi 0,000012/derajat celcius.hitunglah panjang besi setelah mengalami pemuaian?
lailatulkaromah
Lt = L₀ x L₀ + α x ΔT = 1 x 1 + 0,000012 x 100 = 1 + 0.0012 = 1,0012 m = 100,12 cm
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Aderachma0313
DIk = l₀ = 100 cm = 1 m Δt = 100 α = 1,2 × 10⁻⁵ Dit = lt Jwb= lt = l₀.(1+α.Δt) lt = 1(1+1,2×10⁻⁵.100) lt = 1 (1+1,2×10⁻³) lt = 1 + 1,2×10⁻³ lt = 1,0012 m lt = 100,12 cm
= 1 x 1 + 0,000012 x 100
= 1 + 0.0012
= 1,0012 m
= 100,12 cm
l₀ = 100 cm = 1 m
Δt = 100
α = 1,2 × 10⁻⁵
Dit = lt
Jwb=
lt = l₀.(1+α.Δt)
lt = 1(1+1,2×10⁻⁵.100)
lt = 1 (1+1,2×10⁻³)
lt = 1 + 1,2×10⁻³
lt = 1,0012 m
lt = 100,12 cm