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t₁= 25°C
t₂=40° C
Δt= t₂-t₁
Δt= 40-25
Δt= 15°C
l₀=2m
α=1,1×10⁻⁵/°C
dit= lt
jwb=
lt= l₀(1+α.Δt)
lt=2(1+1,1×10⁻⁵.15)
lt=2(1+ 1,65×10⁻⁴)
lt=2+3,3×10⁻⁴m
lt=2,00033 m
Lo= 2 m
Δt= (t₁-t₂) = 40-25= 15°C
α= 0,000011 /° C
Dit:
Lt=..?
Penye:
Lt= Lo.(1+α×Δt)
Lt= 2×(1+0,000011×15)
Lt= 2×(1+0,000165)
Lt= 2×1,000165
Lt= 2,00033 meter