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ΔL =190 × 12⁻⁶
ΔL = 0,002280 m
Panjang stelah dipanaskan = 2 + 0,002280 = 2,00280 m
Maaf kalau salah:)
L0 = 2 m
T0 = 25 C
T = 120 C
α = 0,000012/C
dit : L ?
maka :
L = L0 (1+αxΔT)
= 2 (1+0,000012 x (120-25))
= 2 (1 + 0,000012 x 95)
= 2 (1+0,00114)
= 2 x 1,00114
= 2,00228 m