Ada sebuah pelat yang panasnya 30 derajat C yang luasnya 10 m kuadrat. apa bila suhunya dinaikkan menjadi 90 derajat C dsak koefisien muai panjang besi sebesar 0,000012/derajat C ,maka tentukan luas pelat besi tersebut?
liliput01
Diket: Ao = 10 m² t1 = 30'C t2 = 90'C α = 0,000012/'C
Ditanya : At......? At = Ao ( 1 + β (t2 - t1)) At = Ao ( 1 + 2α (t2 - t1)) At = 10 ( 1 + 2x0,000012 (90 - 30)) At = 10 ( 1 + 0,000024 (60)) At = 10 ( 1 + 0,00144) At = 10 (1,00144) At = 10,0144 m
Ao = 10 m²
t1 = 30'C
t2 = 90'C
α = 0,000012/'C
Ditanya : At......?
At = Ao ( 1 + β (t2 - t1))
At = Ao ( 1 + 2α (t2 - t1))
At = 10 ( 1 + 2x0,000012 (90 - 30))
At = 10 ( 1 + 0,000024 (60))
At = 10 ( 1 + 0,00144)
At = 10 (1,00144)
At = 10,0144 m