Question

Dengan menggunakan sifat bilangan berpangkat.
dengan caranyaa yaa kakaa yang baik hatiii,..jangan ngarang lhoo besok dikumpulinn soalnyaa.. tuu aku kasihh poin banyakk

Answer 1

Verified answer

Jawabannya:

A. 3^-5 × 3³ : 3^-4
= 3/5 × 27 : 3/4
= 3/5 × 27 × 4/3
= 81/5 × 4/3
= 324/15
= 21,6

B. 2⁴ .2²/2¹ .2^5
= 16. 4 / 2. 32
= 64/64
= 1

C. (0,25)^-2 × (0,25)⁴
= 2/0,25 × 0,00390625
= 0,0078125/0,25
= 0,03125

D. (2×7)³×7²×1/2.7²
= (14)²×49×1/2.49
= 196×49×1/2.49
= 98×49.49
= 4802. 49
= 235298

E. ((3^0. 5²/5²)²)³
= ((3. 25/25)²)³
= ((75/25)²)³
= ((5)²)³
= (25)³
= 15625

# Semoga Membantu
Maaf Kalo Salah

Answer 2

MyMateri : Eksponen
Kelas : X

a.) 3^-5 × 3^3 : 3^-4
= 3^-5+3
= 3^-2
= 3^-2-(-4)
= 3^-2+4
= 3^2
= 9

b.) 2^4 . 2^2 / 2^1 . 2^5
= 2^4+2 / 2^1+5
= 2^6 / 2^6
= 1

c.) (0, 25)^-2 × (0, 25)^4
= (0, 25)^-2 + 4
= (0, 25)^2
= 1 / 16

d.) (2 × 7)^3 × 7^2 × 1 / 2 . 7^5
= (2)^3 (7)^3 × 7^2 × 1 / 2 . 7^5
= 8 (7)^3+2 × 1 / 2 . 7^5
= 4 (7)^5 × 1 / 7^5
= 4

e.) ((3^0 . 5^2 / 5^2)^2)^3
= (3^0 . 5^2 / 5^2)^2×3
= (1 . 5^2 / 5^2)^6
= (5^2 / 5^2)^6
= (1)^6
= 1


Semoga Membantu..