Respuesta:
Los valores de x es 14 e y es 5
Explicación paso a paso:
Teorema de thales
Hallamos x:
[tex]\frac{4}{8}=\frac{7}{x} \\\\(4)\times (x) = (8)\times (7) \\\\4x= 56 \\\\x = \frac{56}{4} \\\\x= 14[/tex]
Hallamos y:
[tex]\frac{7}{y}=\frac{21}{7+x} \\\\\\\frac{7}{y}=\frac{21}{7+14}\\\\\frac{7}{y}=\frac{21}{15} \\\\(7)\times (15) = (21)\times (y) \\\\105= 21y \\\\ \frac{105}{21} = y \\\\5= y[/tex]
\begin{gathered}\frac{4}{8}=\frac{7}{x} \\\\(4)\times (x) = (8)\times (7) \\\\4x= 56 \\\\x = \frac{56}{4} \\\\x= 14\end{gathered}
8
4
=
x
7
(4)×(x)=(8)×(7)
4x=56
x=
56
x=14
\begin{gathered}\frac{7}{y}=\frac{21}{7+x} \\\\\\\frac{7}{y}=\frac{21}{7+14}\\\\\frac{7}{y}=\frac{21}{15} \\\\(7)\times (15) = (21)\times (y) \\\\105= 21y \\\\ \frac{105}{21} = y \\\\5= y\end{gathered}
y
7+x
21
7+14
15
(7)×(15)=(21)×(y)
105=21y
105
=y
5=y
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Respuesta:
Los valores de x es 14 e y es 5
Explicación paso a paso:
Teorema de thales
Hallamos x:
[tex]\frac{4}{8}=\frac{7}{x} \\\\(4)\times (x) = (8)\times (7) \\\\4x= 56 \\\\x = \frac{56}{4} \\\\x= 14[/tex]
Hallamos y:
[tex]\frac{7}{y}=\frac{21}{7+x} \\\\\\\frac{7}{y}=\frac{21}{7+14}\\\\\frac{7}{y}=\frac{21}{15} \\\\(7)\times (15) = (21)\times (y) \\\\105= 21y \\\\ \frac{105}{21} = y \\\\5= y[/tex]
Los valores de x es 14 e y es 5
Respuesta:
Los valores de x es 14 e y es 5
Explicación paso a paso:
Teorema de thales
Hallamos x:
\begin{gathered}\frac{4}{8}=\frac{7}{x} \\\\(4)\times (x) = (8)\times (7) \\\\4x= 56 \\\\x = \frac{56}{4} \\\\x= 14\end{gathered}
8
4
=
x
7
(4)×(x)=(8)×(7)
4x=56
x=
4
56
x=14
Hallamos y:
\begin{gathered}\frac{7}{y}=\frac{21}{7+x} \\\\\\\frac{7}{y}=\frac{21}{7+14}\\\\\frac{7}{y}=\frac{21}{15} \\\\(7)\times (15) = (21)\times (y) \\\\105= 21y \\\\ \frac{105}{21} = y \\\\5= y\end{gathered}
y
7
=
7+x
21
y
7
=
7+14
21
y
7
=
15
21
(7)×(15)=(21)×(y)
105=21y
21
105
=y
5=y
Los valores de x es 14 e y es 5