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B
2. muatan total elektron,
Q = jumlah elektron x muatan satu elektron
Q = 4 x 10^19 x 1.6 x 10^-19 = 6.4 C
maka arus yang mengalir adalah
I = Q/ Δt = 6.4 / 10 = 0.64 A
E
3. n = 3
Rm = 140 Ω
Rm = (n - 1) Rv
140 = 2 Rv
Rv = 70 Ω
A
4. Luas ujung batang P = π x r²
A.p = π x [1/2(d)]²
A.p = (1/4) πd²
Luas ujung batang Q = a² (persegi)
maka
Q terhadap P
a² = (1/4)πd²
a = (√π)d / 2
D