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Persamaan simpangan
y = A sin (ωt - kx)
y = 0,5 sin (2t + 0,4x)
dari kesetaraan kedua persamaan diperoleh
A = 0,5 m
ω = 2 rad/s
k = 0,4 m⁻¹
a][ amplitudo
A = 0,5 m ←
c][ frekuensi
ω = 2π f
2 = 2π f
f = 1/π Hz ←
b][ periode
T = 1/f
T = 1 / (1/π) = π s ←
d][ panjang gelombang
k = 2π / λ
0,4 = 2π / λ
λ = 2π / 0,4 = 5π m ←
e][ kecepatan rambat
v = ω / k atau v = λ f
= 2 / 0,4 = 5π · 1/π
= 5 m/s ← = 5 m/s ←