Jawab:
Peluang
P(A) = 1 - P(A')
Penjelasan dengan langkah-langkah:
A= cacat
P(A) = 0,02
B = layak
P(B) = 1 - P(A)
n = 6.000
Banyak lampu yang layak = P(B) x n
= (1 - 0,02) x 6.000
= 0.98 x 6.000
= 5.880 lampu
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawab:
Peluang
P(A) = 1 - P(A')
Penjelasan dengan langkah-langkah:
A= cacat
P(A) = 0,02
B = layak
P(B) = 1 - P(A)
n = 6.000
Banyak lampu yang layak = P(B) x n
= (1 - 0,02) x 6.000
= 0.98 x 6.000
= 5.880 lampu