Dari suatu deret geometri tak hingga diketahui suku ke2 = 24 dan suku ke5= 3 maka suku pertama deret tersebut adalah
Takamori37
![U_2=ar=24 \\ U_5=ar^4=3 \\ \\ \displaystyle \frac{U_5}{U_2}=\frac{U_5}{U_2} \\ \\ \frac{ar^4}{ar}=\frac{3}{24} \\ r^3=\frac{1}{8} \\ r=\sqrt[3]{\frac{1}{8}} \\ \\ r=\frac{1}{2} \\ $Diketahui :$ \\ ar=24 \\ a\times\frac{1}{2}=24 \\ a=24\times 2 \\ a=48](https://tex.z-dn.net/?f=U_2%3Dar%3D24+%5C%5C+U_5%3Dar%5E4%3D3+%5C%5C+%5C%5C+%5Cdisplaystyle+%5Cfrac%7BU_5%7D%7BU_2%7D%3D%5Cfrac%7BU_5%7D%7BU_2%7D+%5C%5C+%5C%5C+%5Cfrac%7Bar%5E4%7D%7Bar%7D%3D%5Cfrac%7B3%7D%7B24%7D+%5C%5C+r%5E3%3D%5Cfrac%7B1%7D%7B8%7D+%5C%5C+r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D+%5C%5C+%5C%5C+r%3D%5Cfrac%7B1%7D%7B2%7D+%5C%5C+%24Diketahui+%3A%24+%5C%5C+ar%3D24+%5C%5C+a%5Ctimes%5Cfrac%7B1%7D%7B2%7D%3D24+%5C%5C+a%3D24%5Ctimes+2+%5C%5C+a%3D48 "U_2=ar=24 \\ U_5=ar^4=3 \\ \\ \displaystyle \frac{U_5}{U_2}=\frac{U_5}{U_2} \\ \\ \frac{ar^4}{ar}=\frac{3}{24} \\ r^3=\frac{1}{8} \\ r=\sqrt[3]{\frac{1}{8}} \\ \\ r=\frac{1}{2} \\ $Diketahui :$ \\ ar=24 \\ a\times\frac{1}{2}=24 \\ a=24\times 2 \\ a=48")
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