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U5 / a+4b = 144
met eliminasi
a+2b = 36 ⇔ 2a+4b = 72
a+4b = 144 ⇔ a +4b = 144
a = -72
met subtitusi
a + 2b = 36
-72 + 2b = 36
2b = 108
b = 54
maka
Sn = 1/2.n (2a +(n-1)b)
S10 = 1/2 . 10 (2 . -72 + 9 . 54)
S10 = 5 (-144 + 486)
S10 = 5 . 342
S10 = 1710
(u5 + u7)...a + 4b + a + 6b = 144
2a + 10b = 144
-----------2a + 10b = 144
---------- 2a + 4b = 72
6b = 72
b= 12
a = 36 - 24 = 12
u10 = a + 9b = 12 + 9*12 = 120
s10 = 1/2n ( a + u10)
= 1/2 *10 (12 + 120)
= 660