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Total siswa = 1.000
Jika diandaikan A = p, B = q, i = r
A = IAIA + IAi
A = p² + 2pr
320 = p² + 2pr
Golongan darah AB (IAIB)
AB = 2pq
40 = 2pq
20 = pq
Frekuensi pq = 20 / 1.000 = 0,02
Golongan darah B
B = IBIB + IBi
B = q² + 2qr
p = 1 - √(B + O)
p = 1 - √(0,015 + O)
q = 1 - √(A + O)
q = 1 - √(0,032 + O)
Total = A + B + AB + O
O = Total - (A + B + AB)
O = 1.000 - (320 + 150 + 40)
O = 1.000 - (510)
O = 490
Frekuensi O = 490 / 1.000 = 0,49
p = 1 - √(B + O)
p = 1 - √(0,15 + 0,49)
p = 1 - √(0,64)
p = 1 - 0,8
p = 0,2
Jadi, jawabannya yang
(B)