Dari deret aritmatika diketahui banyak sukunya 20, suku pertamanya 5, dan jumlah semua sukunya 670. Suku ke 12 deret tersebut adalah ?
yolanda445
Dik = n = 20 a = 5 sn = 670 dit U12 ? jwb sn = n : 2 (2xa + (n-1)b) s 20 = 20 : 2 ( 2x5 + (20-1)b 670 = 10 (10+ 19b) 670 = 100 +190b 670-100 = 190 b 570 = 190 b 570 : 190 = b 3 = b
Un = a + (n-1)b U12 = 5 + (12-1) 3 U 12 = 5 + 11.3 U12 = 5 +33 U12 = 38
10 votes Thanks 12
Yuniangelina123
dik = n = 20
a = 5
sn = 670
dit U12 ?
JAWAB :
sn = n : 2 (2xa + (n-1)b)
s 20 = 20 : 2 ( 2x5 + (20-1)b
670 = 10 (10+ 19b)
670 = 100 +190b
670-100 = 190 b
570 = 190 b
570 : 190 = b
3 = b
Un = a + (n-1)b
U12 = 5 + (12-1) 3
U 12 = 5 + 11.3
U12 = 5 +33
U12 = 38
a = 5
sn = 670
dit U12 ?
jwb
sn = n : 2 (2xa + (n-1)b)
s 20 = 20 : 2 ( 2x5 + (20-1)b
670 = 10 (10+ 19b)
670 = 100 +190b
670-100 = 190 b
570 = 190 b
570 : 190 = b
3 = b
Un = a + (n-1)b
U12 = 5 + (12-1) 3
U 12 = 5 + 11.3
U12 = 5 +33
U12 = 38
670 = ( 2.5 + 19b )
670 = 10 ( 10 + 19b)
670 = 100 + 190b
670 - 100 = 190b
570 = 190b
b = = 3
= 5 + ( 12 - 1 ) 3
= 5 + 11 x 3
= 5 + 33 = 38