Dany jest wielomian W(x)=x (do szescianu)+2x(kwadrat)-x. Oblicz W(pierwiastek z 2 minus 2).
Zad.2Wielomian W(x)=xkwadrat+x-2.Zatem A.W(-2)+1<0 B.W(1)xW(-2)>0 C.W(-2+1)=0 D.W(1).W(-2)=0
Zad3.Liczby 6,x,y,z,9 tworzą ciąg arytmetyczny.Oblicz x,y,z
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1]
W(√2-2)=(√2-2)³+2(√2-2)²-√2+2=
2√2-12+12√2-8+2(2-4√2+4)-√2+2=
13√2-18+4-8√2+8=
5√2-6
2]
W(x)=x²+x-2
W(-2)=(-2)²-2-2=0
w(-2)+1<0
0+1<0 FAŁSZ
W(1)=1+1-2=0
W(-2)=0
W(1)×W(-2)>0
FAŁSZ
W(-2+1)=W(-1)=(-1)²-1-2=-2
FAŁSZ
W(-2)=0 PRAWDA
ODP. D]
3]
a₁=6
a₅=9
a₅=a₁+4r
9=6+4r
4r=9-6
r=¾
............
x=6+¾=6¾
y=6¾+¾=7½
z=7½+¾=8¼